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2 years ago

6

Sorry I keep asking questions, but if two forces on an object are balanced, will it move? (Im also trying to get rid of my point

s) XD

2 answers:

Dmitrij [34]2 years ago

6 0

If they are equal amounts in force then No it won't.

muminat2 years ago

4 0

If the two forces are acting on the object in opposite directions(ex: push from the back and a push from the front), the object will not move.

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A tube of water is open on one end to the environment while the other end is closed. The height of the water relative to the bas

Andreas93 [3]

Answer:

<em>1.06 atm</em>

Explanation:

On the open end of the tube, the pressure will be the sum of atmospheric pressure and the pressure due to the height of water

The pressure due to a height of water = ρgh

where ρ is the density of water = 1000 kg/m^3

g is the acceleration due to gravity = 9.81 m/s^2

h is the height of the water column

The height of water column on the open end = 100 cm = 1 m

pressure on this end = ρgh = 1000 x 9.81 x 1 = 9810 Pa

Atmospheric pressure = 101325 Pa

The total pressure on the open end = 101325 Pa + 9810 Pa = <em>111135 Pa</em>

The pressure due to the water column on the closed end = ρgh

The height of the water in the closed end = 40 cm = 0.4 m

The pressure due to this column of water = 1000 x 9.81 x 0.4 = <em>3924 Pa</em>

The resultant pressure on the water on the top of the closed end of the tube = 111135 Pa - 3924 Pa =<em> 107211 Pa</em>

In atm unit, this pressure = 107211/101325 = <em>1.06 atm</em>

7 0

2 years ago

A proton, an alpha particle (a bare helium nucleus), and a singly ionized helium atom are accelerated through a potential differ

ra1l [238]

Answer:

The correct question is:

"Find the energy each gains"

The energy gained by a charged particle accelerated through a potential difference is given by

$\Delta U = q\Delta V$

where

q is the charge of the particle

$\Delta V$ is the potential difference

For a proton,

$q=+e=1.6\cdot 10^{-19}C$

And since $\Delta V=100 V$

The energy gained by the proton is

$\Delta U=(1.6\cdot 10^{-19})(100)=1.6\cdot 10^{-17}J$

For an alpha particle,

$q=+2e=3.2\cdot 10^{-19}C$

Therefore, the energy gained is

$\Delta U=(3.2\cdot 10^{-19})(100)=3.2\cdot 10^{-17}J$

Finally, for a singly ionized helium nucleus (a helium nucleus that has lost one electron)

$q=+e=1.6\cdot 10^{-19}C$

So the energy gained is the same as the proton:

$\Delta U=(1.6\cdot 10^{-19})(100)=1.6\cdot 10^{-17}J$

6 0

2 years ago

HELP When the forces are applied in the same direction, how do you determine net force?

aleksklad [387]

Answer:

Explanation:

If two forces act on an object in the same direction, the net force is equal to the sum of the two forces.

5 0

2 years ago

A student runs 35 m east, then 12 m west. What is the distance run by the student?

lora16 [44]

47m total just add them up 35 + 12 = 47

4 0

2 years ago

Read 2 more answers

Can someone please give me the (Answers) to this? ... please ...<br><br> I need help….

IceJOKER [234]

#1.

<em>Car </em>1<em> weighs </em>300 kilograms<em> and is moving right at </em>3 meters per second (m/s)

v1 (before) = 3 m/s

v2 (before) = -1 m/s

v1 (after) = 0.5 m/s

#2.

Law of conservation of momentum

momentum before collorion = momentim after collosion

MV + mv = MV' + mv'

1500x25+ 1000x5

37500 + 15000

6 0

1 year ago