Answer:
12 g of choloracetic acid
Explanation:
The buffer equilibrium is:
HCH₂ClCO₂ ⇄ CH₂ClCO₂⁻ + H⁺
pka= -log ka =
Ka: 1,3x10⁻³ = [CH₂ClCO₂⁻] [H⁺] / [HCH₂ClCO₂]
By Henderson-Hasselbalch equation:
pH = pka + log₁₀ [A⁻] / [HA]
3,01 = 2,89 + log₁₀ [A⁻] / [HA]
1,318 = [A⁻] / [HA]
As molar concentration of chloroacetic acid (HA) is 0,20M
[A⁻] = 0,26 mol/L
The volume is 500 mL ≡ 0,5 L
0,26mol/L × 0,5 L = 0,13 moles of chloroacetic acid. In grams:
0,13 mol × (94,5g / 1mol) = <em>12 g of choloracetic acid</em>
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I hope it helps!
<u>Answer:</u> The acceleration of the object is 2m/s^2. If net force increases, acceleration will also increase and if mass increases, the acceleration will decrease.
<u>Explanation:</u>
Force is defined as the product of object's mass and acceleration.
Mathematically,
F = ma ......(1)
or,
a = F/m .....(2)
where,
F = Force exerted on an object = 60N
m = mass of an object = 30kg
a = acceleration of the object = ?
Putting values in above equation, we get:
a = 60 kg.m/s^2/30 kg = 2m/s^2
The acceleration of the car is 2m/s^2.
From equation 2, it is visible that acceleration is directly proportional to force. This means that \if force increases, acceleration also increases.
And acceleration is inversely proportional to mass of the object. This means that if mass increases, the acceleration decreases.
Hence, if net force increases, acceleration will also increase and if mass increases, the acceleration will decrease.
Answer:
44.8 L
Explanation:
Ideal Gas Equation -
i.e.,
PV = nRT
where,
P = pressure
V = volume
n = moles
R = universal gas constant
T = temperature
Using the information given in the question, Volume of the gas can be calculated -
P = 101.3 kPa
V = ?
n = 2.00 moles
R = 8.31
T = 0 degree C = 273.15 K
Using the above data, and putting the data in the respective formula -
PV = nRT
101.3 kPa * V = 2.00 moles * 8.31 * 273.15 K
V = 44.8 L
Hence, the volume of the given gas = 44.8 L
Answer:
For oxygen: mass % O = (mass of 1 mol of oxygen/mass of 1 mol of CO2) x 100. mass % O = (32.00 g / 44.01 g) x 100. mass % O = 72.71 %
Explanation: