Answer:
a)
if 1 quarter = $ 0.25
1 dime = $ 0.10
1 penny = $ 0.01
so to make the total of $1.08 and its is also required to calculate the number of each coins present without being able to make change for a dollar
therefore we say;
1 Quarter + 8 dimes + 3 penny
: ( 1 × 0.25 ) + ( 8 × 0.10 ) + ( 3 × 0.01 )
: 0.25 + 0.80 + 0.03 = $ 1.08
b)
Now if you have a 4 Quarters, you have change for $1.
If you have 5 dimes, you have change for 2 Quarters.
If you have nickel; one of those can combine with 2 dimes to have a change for a Quarter.
If you have 5 pennies, you have enough change for 1 nickel
Therefore
(4-1)×0.25 + (5-1)×0.1 + (0×0.05) + (5-1)×0.01 = x
(3 × 0.25) + ( 4 × 0.1) + 0 + ( 4 × 0.01) = x
x = 0.75 + 0.4 + 0.04
x = $ 1.19
PROVED
We conclude that, if working at the same rate, to make 374 units, she needs to work for 17 hours.
<h3>
At the same rate, how many hours would she have to work to make 374?</h3>
We know that Mary makes 242 units of something in 11 hours of work, then her rate of work is:
R = (242 units)/(11 hours) = 22 units per hour.
Now, if she wants to make 374 units, then she needs to work for a time T, such that:
(22 units per hour)*T = 374 units.
Solving that linear equation for T, we get:
T = (374 units)/(22 units per hour) = 17 hours
We conclude that, if working at the same rate, to make 374 units, she needs to work for 17 hours.
If you want to learn more about linear equations:
brainly.com/question/1884491
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Answer:
Step-by-step explanation:
GIVEN: Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams Three players in each team.
TO FIND: how many different ways can they be put into two teams of three players.
SOLUTION:
Total number of players
total teams to be formed
total players in one team
we have to number of ways of selecting players for one team, rest will go in other team.
Total number of ways of selecting players
Hence total number of different ways in which they can be put into two different teams is
Answer:
(3a-7) (2a-1) is the answer
Step-by-step explanation: