Answer:
Following are the solution to the given points:
Step-by-step explanation:
Given values:
Total staff=40
In point a:
To calculate the median number first we arrange the value into ascending order and then collect the even numbers of calls that were also made. Its average of the middle terms is thus the median.
The midterms =55 and 59 so,
Median =
In point b:
First-quarter
The first quarterlies are
therefore the multiply of 0.5 by calculating the difference of the 7th and 8th term are:
therefore the it is multiply by the 0.5 for the difference of the 22nd and 23rd term:
In point c:
First decile
In point d:
quartiles are:
The right answers for the decile are:
As for will be available.
Answer:
1.35
Step-by-step explanation:
I believe this is right but it could be wrong. Hope this helps! <3
The answer is: " 128 oz. " .
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There are: " 128 oz. " (in " 8 lbs." ) .
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Explanation:
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Set up a proportion; as a fraction; as follows:
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400/ 25 = x / 8 ;
in which: "x" = the number of "ounces [oz.] there are in "8 lbs." ;
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We shall solve for "x" , the answer to the problem:
Cross-factor multiply:
25x = (400) * 8 ;
→ 25x = 3200 ;
Divide each side of the equation by "25" ; to isolate "x" on one side of the equation; & to solve for "x" ;
→ 25x / 25 = 3200 / 25 ;
→ x = 128 .
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Answer: " 128 oz. " .
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There are: " 128 oz. " (in " 8 lbs." ) .
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Note of interest: " 16 oz. = 1 lb. " (exact conversion).
So; "8 lbs. <span>= ?</span> oz. " ;
→ " 8 lbs. * (16 oz/ 1 lb) = ( 8 * 16) oz. = 128 oz. ; → which is our answer!
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Answer:
A(t) = amount remaining in t years
= A0ekt, where A0 is the initial amount and k is a constant to be determined.
Since A(1690) = (1/2)A0 and A0 = 80,
we have 40 = 80e1690k
1/2 = e1690k
ln(1/2) = 1690k
k = -0.0004
So, A(t) = 80e-0.0004t
Therefore, A(430) = 80e-0.0004(430)
= 80e-0.172
≈ 67.4 g
Step-by-step explanation: