Answer:
A. B and C are functions
Step-by-step explanation:
Given
See attachment for mapping diagrams
Required
Which represent function
For a mapping to be considered a function, each element of the input set must only point to 1 element of the output set.
Base on the above analysis, we have:
<u>Map A</u>
1 points to 6; 2 to 7; 3 to 8; and 4 to 9
<em>This is a function</em>
<u>Map B</u>
2 points to 0; 4 to 0; 6 to 0; and 8 to 0
<em>This is a function</em>
<u></u>
<u>Map C</u>
1 points to 8; 3 to 8; 5 to 9; and 7 to 9
<em>This is a function</em>
<u>Map D</u>
0 points to 2 and 5; 3 points 7 and 9
<em>This is not a function</em>
Answer:
x = 1 - 5t
y = t
z = 1 - 5t
Step-by-step explanation:
For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).
Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.
We have x = e^(-5t)cos5t
at t = 1, x = e^(-5)cos5
at t = 0, x = 1
y = e^(-5t)sin5t
at t = 1, y = e^(-5)sin5
at t = 0, y = 0
z = e^(-5t)
at t = 1, z = e^(-5)
at t = 0, z = 1
Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.
In vector notation, the curve
r(t) = xi + yj + zk
= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k
r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k
r'(0) = -5i + j - 5k
is a vector tangent at the point.
We get the parametric equation from this.
x = x(0) + tx'(0)
= 1 - 5t
y = y(0) + ty'(0)
= t
z = z(0) + tz'(0)
= 1 - 5t
Answer: 10 bottles
Step-by-step explanation: 8 x 5 = 40. 2 x 5 = 10
First let you know what to do. OK. Going to drag a ruler. Across the paper. Vertically. And if it touches 2 points on the grid. Then it fails the test.
Number = 125
Here, ∛125 = 5
so, in exponential form, it would be: 5³
So, your final answer is 5³
Hope this helps!
