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2 years ago

Could anyone answer please?

Mathematics

1 answer:

Goryan [66]2 years ago

7 0

1. 26
2. 20
3. 38
4. 25
5. 47

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EastWind [94]

Answer:

7. 163 pizzas

8. 4 pencils

Step-by-step explanation:

7. 1,956 divided by 12 equals 163

8. $\frac{829}{25}$ = 33 $\frac{4}{25}$

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1 year ago

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PLEASE HELP!! What is the slope of the line on the graph?

sammy [17]

Answer:

Step-by-step explanation:

Slope formula is the difference of the y values divided by the difference of x values. Choose to points. I chose (-2,-1) and (0,3). 3-(-1) is equal to 4. 0-(-2) is equal to 2. 4 divided by 2 is two.

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2 years ago

Round 6.94729776259 to 5 decimal places.

blagie [28]

Answer

6.9473

Step-by-step explanation:

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2 years ago

Hello, can someone pls help me ty!

max2010maxim [7]

Answer:

C, 5/2

Step-by-step explanation:

3 I2x -1I + 4 = 16

Isolate absolute value:

3 I2x -1I + 4 - 4 = 16 - 4

3 I2x -1I= 12

(3 I2x -1I) / 3 = 12 / 3

I2x -1I= 4

Since the question is only asking for the positive, all you need to solve for is the +4. Solve for x

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2x -1 + 1 = 4 +1

2x = 5

2x / 2 = 5 / 2

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2 years ago

The SAT Reasoning Test (formerly called the Scholastic Aptitude Test) is perhaps the most widely used standardized test for coll

slamgirl [31]

Answer:

The score is $x = 1884$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 1500$

The standard deviation is $\sigma = 300$

From the question we are told that the score follow a normal distribution

i.e $X \~ \ N( 1500 , 300)$

The proportion of score in the top 10% is mathematically

$P(X > x ) = P( \frac{X - \mu}{\sigma } > \frac{x - \mu}{\sigma } ) = 0.10$

Where x is the minimum score required to be in the top 10%

Now the $\frac{X - \mu}{\sigma } = Z (The \ Standardized \ value \ of \ X)$

$P(X > x ) = P( Z > \frac{x - \mu}{\sigma } ) = 0.10$

$P(X > x ) = P( Z > \frac{x - 1500}{300} ) = 0.10$

So the critical value of 0.10 from the normal distribution table is $Z_{0.10} = 1.28$

$\frac{x - 1500}{300} = 1.28$

$x = 1884$

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2 years ago