Could I have a picture of the model which is shown?
<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
Answer:
1) 2/3
2) 1/2
3) 4/5
4) 3/4
Step-by-step explanation:
4/6 can be divided by 2 to get 2/3 in its simplest
2/4 can be divided by 2 to get 1/2 in its simplest
12/15 can be divided by 3 to get 4/5 in its simplest
6/8 can be divided by 2 to get 3/4 in its simplest
Answer:
x=14
Step-by-step explanation:
you should set up your problem like this:
5x=3x+28
use order of operations aka PEMDAS to solve
you're answer is 14
Answer:
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