Answer:
For both sets of data, the median is equal to the mean.
The interquartile range (IQR) is greater for M's classes than J's classes.
Step-by-step explanation:
<u>J's Classes:</u>
23, 25, 27, 28, 32
Median: 27
Mean: 27
Mean Absolute Deviation: 2.4
Interquartile Range: 3
<u>M's Classes:</u>
20, 24, 26, 29, 31
Median: 26
Mean: 26
Mean Absolute Deviation: 3.2
Interquartile Range: 5
Answer:
20/9
Step-by-step explanation:
Alright, so by using the "keep me, change me, turn me over" method - we can easily solve this:
<em>I hope I was of assistance!</em> <em><u>#SpreadTheLove <3</u></em>
It would be 8 to the 8th power
Answer:
Range= (0,∞) and (-∞,0)
Step-by-step explanation:
Theres no real process to finding this out you just look at what type of function you have, your graph and your asymptote. We can see that the parts above the asymptote go up and towards ∞ and the part below goes down to -∞ but they can not cross 0