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Ostrovityanka [42]

2 years ago

10

Of the 15-year-olds at a karate school, 5 have black belts and 9 have brown belts. Among the 16-year-olds, 13 have black belts a

nd 19 have brown belts. Which age group has a lower ratio of black belts to brown belts?

1 answer:

Effectus [21]2 years ago

5 0

Answer:

the 15 year olds do

Step-by-step explanation:

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The sum of the three angles in a triangle is 180 degrees. One of the angle measures 30 degrees, and the second angle measures 75

Molodets [167]

Answer:

75 degrees

Step-by-step explanation:

30 + 75 = 105

180 - 105 = 75

4 0

2 years ago

Read 2 more answers

Please help! geometry problem 3!

Vilka [71]

Comment
|First of all, the triangles are equal by ASA the way the diagram has been marked.

B and E are both right angles.
Side BC = Side DE
<BCA =< EDA

So triangle BCA = triangle EDA

Now to the letters.
x = y - 1 Add 1 to both sides.
x + 1 = y (1)
3x - 2 = 2y + 1 Subtract 1 from both sides.
3x -2 - 1 = 2y
3x - 3 = 2y Divide by 2
3x/2 - 3/2 = 2y/2
1.5x - 1.5 = y (2)

Step One
Since (1) and (2) both have y isolated on their respective right sides, they can be equated.

1.5x - 1.5 = x + 1 Take an x from both sides.
0.5x - 1.5 = x - x + 1
0.5x - 1.5 = 1 Add 1.5 to both sides.
0.5x = 1 + 1.5
0.5x = 2.5 Divide 0.5 on both sides.
0.5x/0.5 = 2.5/0.5

x = 5

Now we need a y value.
x = y - 1
5 = y - 1 Add 1 to both sides.
5 + 1 = y - 1 + 1
6 = y

So the 2 sides and the 2 angles are equal when
x = 5
y = 6

C Answer <<<<<<

4 0

2 years ago

Divide 5 in a ratio of 1:2:3

anastassius [24]

In plain and short, we simply divide 5 by (1+2+3) and then distribute the pieces likewise

$\bf 5\qquad 1:2:3\qquad \cfrac{5}{1+2+3}\implies \cfrac{5}{6}
\\\\\\
\stackrel{\textit{ratio of 1}}{1\left( \frac{5}{6} \right)}\qquad \stackrel{\textit{ratio of 2}}{2\left( \frac{5}{6} \right)}\qquad \stackrel{\textit{ratio of 3}}{3\left( \frac{5}{6} \right)}\qquad \implies \qquad \frac{5}{6}~:~\frac{5}{3}~:~\frac{5}{2}$

add the ratios up, and you'll get 5.

4 0

2 years ago

A regular decagon has sides that are 8 cm long. What is the area of the figure? Round to the nearest whole number.

blsea [12.9K]

<u>Given</u>:

Given that the regular decagon has sides that are 8 cm long.

We need to determine the area of the regular decagon.

<u>Area of the regular decagon:</u>

The area of the regular decagon can be determined using the formula,

$A=\frac{s^{2} n}{4 \tan \left(\frac{180}{n}\right)}$

where s is the length of the side and n is the number of sides.

Substituting s = 8 and n = 10, we get;

$A=\frac{8^{2} \times 10}{4 \tan \left(\frac{180}{10}\right)}$

Simplifying, we get;

$A=\frac{64 \times 10}{4 (\tan \ 18)}$

$A=\frac{640}{4 (0.325)}$

$A=\frac{640}{1.3}$

$A=642.3$

Rounding off to the nearest whole number, we get;

$A=642 \ cm^2$

Thus, the area of the regular decagon is 642 cm²

Hence, Option B is the correct answer.

5 0

2 years ago

Which equation is the slope-intercept form of the line that passes through (1, 2) and is parallel to the graph of y = 8/3x?

Blizzard [7]

Answer:

5

Step-by-step explanation:

it is five

3 0

2 years ago