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2 years ago

How many solutions does the system of inequalities graphed below have?

Mathematics

1 answer:

kompoz [17]2 years ago

4 0

I would say D) Infinitely many.

The question is slightly confusing but what I can tell is there are at least 3 points on the graph that are touched so it can't be asking about that since we have answers like 0, 1 and 2.

So next, we can look at the slopes aka how far the lines reach and cross. They seem to keep going on and on without stopping at any visible point on the graph. So you can say there are infinitely many solutions with any real number.

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Verify identity: (sec(x)-csc(x))/(sec(x)+csc(x))=(tan(x)-1)/(tan(x)+1)

Nikitich [7]

So hmmm let's do the left-hand-side first

$\bf \cfrac{sec(x)-csc(x)}{sec(x)+csc(x)}\implies \cfrac{\frac{1}{cos(x)}-\frac{1}{sin(x)}}{\frac{1}{cos(x)}+\frac{1}{sin(x)}}\implies 
\cfrac{\frac{sin(x)-cos(x)}{cos(x)sin(x)}}{\frac{sin(x)+cos(x)}{cos(x)sin(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)sin(x)}\cdot \cfrac{cos(x)sin(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

now, let's do the right-hand-side then

$\bf \cfrac{tan(x)-1}{tan(x)+1}\implies \cfrac{\frac{sin(x)}{cos(x)}-1}{\frac{sin(x)}{cos(x)}+1}\implies \cfrac{\frac{sin(x)-cos(x)}{cos(x)}}{\frac{sin(x)+cos(x)}{cos(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)}\cdot \cfrac{cos(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

7 0

2 years ago

2:5 is how much out of 27

spayn [35]

13.5 is your answer, here u are

5 0

2 years ago

Which number is prime? 85 49 70 31

Citrus2011 [14]

Answer: 31 is a prime number because only 1 times itself equals 31. no other two factors equal 31 as a product.

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Describe the pattern in the numbers. Write the next number in the pattern. 1, 2/3, 1/3, 0

olga2289 [7]

Answer:

-1/3

Step-by-step explanation:

its subtracting 1/3 every time

6 0

2 years ago

WILL GIVE BRAINLIEST TO BEST RESPONSE!

Monica [59]

You are given the X value, replace x with 2 in the first equation to solve for y:

y=2x +3

y = 2(2) +3

y = 4+3

y = 7

Now replace y with 7 and x iwth 2 in the second equation and solve for k:

y = -x +k

7 = -2 +k

Add 2 to both sides:

9 = k

so k = 9

The point is given as k-2, which is 9-2 = 7, which is what y equals in the first equation.

K = 9

5 0

3 years ago