Write a balanced chemical equation for the decomposition of solid sodium sulfide in aqueous solution. A) Na2S(s) → Na+(aq) + S(s
) B) NaS2(s) → Na+(aq) + 2S2-(aq) C) Na2S(aq) → 2Na+(s) + S2-(s) D) Na2S(s) → 2Na+(aq) + S2-(aq)
2 answers:
Answer: D)
Explanation: Decomposition reaction is a chemical reaction in which one reactant decomposes to give two or more than two products.
The substances which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
Thus when sodium sulfide dissociates in aqueous solution, it gives ions which are present in aqueous form.
You might be interested in
Answer:
the final velocity of the two blocks is
the distance that A slides relative to B is
Explanation:
From the diagram below;
acceleration of A relative to B is :
where
v = u + at
Making t the subject of the formula; we have:
which implies the distance that A slides relative to B.
The final velocities of the two blocks can be determined as follows:
v = u + at
Thus, the final velocity of the two blocks is
Answer:
The magnitude of the net electric field is:
Explanation:
The electric field due to q1 is a vertical positive vector toward q1 (we will call it E1).
On the other hand, the electric field due to q2 is a horizontal positive vector toward q2(We will call it E2).
Knowing this, the <u>magnitude of the net electric</u> field will be the<u> E1 + E2. </u>
Let's find first E1 and E2.
The electric field equation is given by:
Where:
- k is the Coulomb constant (k = 9*10^{9} Nm²/C²)
- q1 is the first charge
- d1 is the distance from q1 to P
And E2 will be:
Finally, we need to use the Pythagoras theorem to find the magnitude of the net electric field.
I hope it helps you!