Based on the percentage that passed English and those who passed Mathematics and those who failed and passed both, the total number of students who appeared in the examination are 60 students.
The number of students who passed only in Math are 12 students.
<h3>What number of students sat in the exam?</h3>
This can be found as:
= Total who passed English only + Total who passed Math only + Total who failed both + Total who passed both
Assuming the total is n, the equation becomes:
n = 0.75n - 21 + 0.55n - 21 + 21 + 0.05n
n = 1.35n - 21
21 = 0.35n
n = 21 / 0.35
= 60 students
The number who passed mathematics only is:
= (60 x 55%) - students who passed both
= 33 - 21
= 12 students
Find out more on Venn diagrams at brainly.com/question/24581814
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Answer: D. This was a random sample. It may have included anyone in attendance.
Step-by-step explanation:
The options are:
A. This was a biased sample. Jim should interview all in attendance.
B. This was a census. Any guest may have participated.
C. This was a random sample. It may not have included anyone in attendance.
D. This was a random sample. It may have included anyone in attendance.
A random sampling is simply referred to as a subset of individuals that are picked from a larger set of individuals.
With regards to the question, Jim wanted to find out what the audience thought about the debate and after the event, he stood at the exit to survey every fifth guest.
This means that it was a random sampling and anyone could have been picked, the sampling wasn't bias.
It’s to prove of the pounds and the congress to put each three out
I like to think of the - or under as the less likely to happen like a cat beating up a bear u don’t want to put your money on the cat so everyone puts there money on the bear making the bear the over and the cat the under