All categories

2 years ago

What are some examples of neutron?

Chemistry

1 answer:

Katena32 [7]2 years ago

7 0

Answer: Almost anything non-electrically charged.

Explanation: An electrically neutral subatomic particle in the baryon family, having a mass of 1.674 × 10&spminus;24 grams (1,838 times that of the electron and slightly greater than that of the proton).

You might be interested in

If the pH of vinegar is 3.0, what is the concentration of H+ in vinegar?

Cerrena [4.2K]

Answer: The concentration of $H^{+}$ ions in vinegar is 0.001 M.

Explanation:

Given: pH = 3.0

pH is the negative logarithm of concentration of hydrogen ion.

The expression for pH is as follows.

$pH = - log [H^{+}]$

Substitute the value into above expression as follows.

$pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M$

Thus, we can conclude that the concentration of $H^{+}$ ions in vinegar is 0.001 M.

5 0

2 years ago

Explain why saltwater is considered a mixture

lutik1710 [3]

Because it is a mix of H2O (water) and NaCl (salt)

3 0

2 years ago

Read 2 more answers

A neutral Atom of silicon-30 contains 14 protons . How many electrons does it have ?

svetoff [14.1K]

14 right??? i hope this helps

3 0

2 years ago

The temperature of a 100.0 g sample of water is raised from 30degrees celsius to 100.0 degrees celsius. How much energy is requi

worty [1.4K]

Answer:

29260J

Explanation:

Given parameters:

Mass of water sample = 100g

Initial temperature = 30°C

Final temperature = 100°C

Unknown:

Energy required for the temperature change = ?

Solution:

The amount of heat required for this temperature change can be derived from the expression below;

H = m c (ΔT)

H is the amount of heat energy

m is the mass

c is the specific heat capacity of water = 4.18J/g°C

ΔT is the change in temperature

Now insert the parameters and solve;

H = 100 x 4.18 x (100 - 30)

H = 100 x 4.18 x 70 = 29260J

6 0

2 years ago

Vanyuwa [196]

Answer:

If the volume of a gas increased from 2 to 6 L while the temperature was held constant, the pressure of the gas decreased by a factor of 3.

Explanation:

Boyle's law that says "The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure." This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

P * V = k

To obtain the proportionality factor k you must make the quotient:

$k=\frac{V2}{V1} =\frac{6 L}{2 L}$

k= 3

This means that if the volume of a gas increased from 2 to 6 L while the temperature was held constant, the pressure of the gas decreased by a factor of 3.

4 0

2 years ago