All categories

2 years ago

A car starting from rest accelerates at a rate of 2 m/sec2 . Find the average speed of this object in the first 10 seconds.

Physics

1 answer:

Jobisdone [24]2 years ago

3 0

Answer:

The final speed of the car in the first 10 seconds will be 20 m/s.

Explanation:

Given that,

Initial speed of the car, u = 0

Acceleration of the car, $a=2\ m/s^2$

Time, t = 10 s

We need to find the speed of the car in the first 10 seconds. It can be calculated using first equation of motion. It is given by :

$v=u+at$

v is the final speed of the car

$v=at$

$v=2\ m/s^2\times 10\ s$

v = 20 m/s

So, the final speed of the car in the first 10 seconds will be 20 m/s. Hence, this is the required solution.

You might be interested in

A motorist traveling with a constant 15m/s passes a school crossing conner where the speed limit is 10m/s,just as a motorist pas

aleksklad [387]

Answer:

The answer is 5 seconds;

Explanation:

<h3>a) We know that the speed(V) is 15 m/s and acc. (a) is 3 m/s^2 </h3><h3>b) The formula for the acceleration is a= $\frac{V}{t}$ ;</h3><h3>Using this formula we can define the next equation:</h3><h3>3 = $\frac{15}{t}$ , where t is the sought time. After solving the equation we get that t is 5; </h3><h3> </h3><h3></h3><h3></h3>

3 0

1 year ago

What happens when you spray your mouth with spray paint?

Mamont248 [21]

You realized that you are stupid....

6 0

2 years ago

Which part of the microscope is responsible for enlarging the specimen?

klio [65]

Answer:

Explanation:

magnifying = enlarging something or making it seem bigger

6 0

2 years ago

Read 2 more answers

A magnetic field is passing through a loop of wire whose area is 0.015 m2. The direction of the magnetic field is parallel to th

Arlecino [84]

This question is incomplete, the complete question is;

A magnetic field is passing through a loop of wire whose area is 0.015 m2. The direction of the magnetic field is parallel to the normal to the loop, and the magnitude of the field is increasing at the rate of 0.20 T/s.

(a) Determine the magnitude of the emf induced in the loop.

(b) Suppose the area of the loop can be enlarged or shrunk. If the magnetic field is increasing as in part (a), at what rate (in m^2/s) should the area be changed at the instant when B = 1.5 T, if the induced emf is to be zero? (Give the magnitude of the rate of change of the area.) (m2/s)

Answer:

a) the magnitude of the emf induced in the loop is 0.003 V

b) dA/dt = 0.002 m²/s

Explanation:

Area of the loop wire A = 0.015 m²

magnitude of the field is increasing dB/dt = 0.20 T/s

Determine the magnitude of the emf induced in the loop.

V = A( dB/dt )

we substitute

V = 0.015 m² × 0.20 T/s

V = 0.003 V

Therefore, the magnitude of the emf induced in the loop is 0.003 V