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2 years ago

In a_____ tax system, the tax rate gets higher as the taxable income gets larger

Mathematics

1 answer:

AnnyKZ [126]2 years ago

3 0

In an income tax system

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In your computation, approximate its value as 3.14.

andrey2020 [161]

Answer: d

Step-by-step explanation:

Find the area of the rectangle.

$A=l*w\\A=(15in)(12in)\\A=180in^2$

Find the area of the base of the semicircle.

$A=\pi r^2$

12 in would be the diameter, divide by 2 to get the radius.

$\frac{12}{2}=6$

Plug this into the formula.

$A=(3.14)(6)^2\\A=113.04in^2$

Since we do not have a full circle but a semi one instead, we must divide our result by 2.

$\frac{113.04}{2}=56.52in^2$

Add both areas.

180+56.52=236.52 $in^2$

7 0

2 years ago

Uptown Country Club only admits members with annual incomes in the top 2.5% of the United States. If the annual individual incom

Verdich [7]

Answer:

$74,600

Step-by-step explanation:

-Given the probability is 2.5%, mean=$55,000 and standard deviation= $10,000

-We find the z value of 2.5%

$p=P(z>\frac{X-\mu}{\sigma})\\\\1.96=P(z$

Hence, the minimum amount of income to be in the top 2.5% is $74,600

5 0

2 years ago

• You use it to form general ideas and rules based on your experiences and

Vladimir79 [104]

Answer: Scientific knowledge?

I’m not really sure what you’re asking, but I hope this helped!

Step-by-step explanation:

6 0

3 years ago

A jet can carry up to 200,000 liters of fuel.it used 130,000 liters of fuel during a flight. What percentage of the fuel capacit

Komok [63]

Percentage=(fuel consumed/ full fuel capacity) *100%
=(130000/200000)*100%
=65%

3 0

1 year ago

A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?

AlekseyPX

Answer:

The width of the sandbox is $42\frac{2}{3} \ ft$ .

Step-by-step explanation:

Given,

Area of the sandbox = $10\frac{2}{3}=\frac{32}{3}\ ft^2$

Length = $\frac{1}{4}\ ft$

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

$Area = Length\times Width$

On substituting the given values, we get;

$\frac{1}{4}\times w=\frac{32}{3}\\$

By cross multiplication method, we get;

$w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft$

Hence The width of the sandbox is $42\frac{2}{3} \ ft$ .

5 0

2 years ago