What happens when a cell that has an internal salt concentration of 0.15M NaCl is placed into a solution of 0.01M NaCl?
1 answer:
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Answer:
CaF2 will not precipitate
Explanation:
Given
Volume of Ca(NO3)2 ml
Molar concentration of Ca(NO3)2
Volume of NaF ml
Molar concentration of NaF
Ksp for CaF2
CaF2 will precipitate if Q for the reaction is greater than ksp of CAF2
Moles of calcium ion
Moles of F- ion
Q is lesser than Ksp value of CaF2. Hence it will not precipitate
The question is incomplete. Complete question is:
<span>Consider the given acid ionization constants. identify the strongest conjugate base.
</span>HNO2(aq) 4.6×10−4
HCHO2(aq) 1.8×10−4
HClO(aq) 2.9×10−8
HCN(aq) 4.9×10−10
.........................................................................................................................
Correct Answer: option 4: HCN(aq) 4.9×10−10
Reason:
According to Lowry and Bronsted theory of acid and base. Stronger the acid, weaker will be the conjugate base.
In present case, ionization constant is highest of HCN i.e. 4.9×
. This signifies that, it is the strongest acid. Hence, conjugate base associated with this acid (i.e. 
) is the weakest.
<span>Consider the given acid ionization constants. identify the strongest conjugate base.
</span>HNO2(aq) 4.6×10−4
HCHO2(aq) 1.8×10−4
HClO(aq) 2.9×10−8
HCN(aq) 4.9×10−10
.........................................................................................................................
Correct Answer: option 4: HCN(aq) 4.9×10−10
Reason:
According to Lowry and Bronsted theory of acid and base. Stronger the acid, weaker will be the conjugate base.
In present case, ionization constant is highest of HCN i.e. 4.9×