Answer:
d.0.48
Explanation:
When a population is in Hardy Weinberg equilibrium the <u>genotypic </u>frequencies are:
freq (AA) = p²
freq (Aa) = 2pq
freq (aa) = q²
<em>p</em> is the frequency of the dominant <em>A</em> allele and <em>q</em> is the frequency of the recessive <em>a</em> allele.
In this population of 100 individuals, 84 martians have the dominant phenotype and 16 have the recessive phenotype.
Therefore:
q²=16/100
q² = 0.16
q=√0.16
q = 0.4
And p+q=1, so:
p = 1 - q
p = 1-0.4
p = 0.6
The frequency of heterozygotes is:
freq (Aa) = 2pq = 2 × 0.4 × 0.6
freq (Aa) = 0.48
Students hypothesized that adding lactose to a sixth test tube would produce the greatest amount of carbon dioxide.
This is because lactose is a sugar molecule that is the food source for the yeast.
Fermentation is a metabolic pathway that occurs anaerobically, meaning in the absence of oxygen (O2). It includes the process of glycolysis with some extra reactions which make alcohol.
Well, different organisms require different things. A single celled bacteria does not need a lot at all compared to a plant or animal. One cell can support a bacrerium. An animal needs many cells to carry out the functions necessary for it to live.
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Answer:
b) false
Explanation:
The given statement is false. the selection process used by the rancher is an example of artificial selection and not natural selection.
Artificial selection is defined as the selection process done by humans on the basis of desirable characters while in natural selection the selection is based on the adaptive characteristics of animals. In the given example rancher choses a desirable character of chicken that lays more eggs.
Hence, the given statement is "false".
