We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

$\text{The weight of average pumpkin}=5\text{ kg}$

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0

3 years ago

Read 2 more answers

Find the number that makes the ratio equivalent 1:3 9:_

dimaraw [331]

Answer:

Step-by-step explanation:

If the ratio is 1:3 multiply that by 9:9 so you effectively get 9:9x3 = 9:27. Or, you can say to yourself if B (3) is 3 times greater than A (1) then B is 3 times greater than 9. So 9x3 = 27

3 0

2 years ago

Evaluate 42,147÷63. Round to the nearest whole number, if necessary.

Harman [31]

Answer:

669 is the answer to this equation

Step-by-step explanation:

brainliest?

4 0

2 years ago

Read 2 more answers