Let x be the length of the garden
and y be the width of the garden.
since you only enclose 3 sides of the garden by a 40 ft fence. so the equation for this is:
2x + y = 40
and the area of the garden is 100 sq ft, so in equation
xy = 100
from equation 1, 2x + y = 40
y = 40 - 2x
substitute to equation 2
xy = 100
x ( 40 - 2x) = 100
40x - 2x^2 = 100
2x^2 - 40x + 100 = 0
x = 2.9 ft
y = 34.5 ft
PHOTOMATH HELPSSSSSS SO MUCHHHHHJJJJJ
Answer:
coordinates of H = (1, 0)
Coordinates of G = ( - 3.6, -2) or (5.6, -2)
Step-by-step explanation:
E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis.
Let the coordinates of H is (x, 0) and G is (a, b).
The length of side EF is
So,
And
Now
Solving (1) and (2)
b = - 2 ,
D) Y=-2x + 1
I think this is the right answer :)
7/1 cheerleaders per squad
x/12 squads
84 cheerleaders in 12 squads
