Now, jump on or back the tens and then the ones to find the answer.

Mathematics

1 answer:

ziro4ka [17]2 years ago

5 0

Answer:

how are you defining tens and ones' places for words?

Step-by-step explanation:

je parle francais

You might be interested in

Flora drew the following graph to answer the question. What was her mistake when she drew her graph? (NO LINKS)

jeyben [28]

Answer:

Her elevation went down too quickly, if she is going down 300 ft per hour at a constant rate, at 1 hour, she should be at 2700 feet. It should take her about 10 hours to get down the mountain.

8 0

2 years ago

Which number produces a rational number when added to 1/5

marin [14]

Answer: 2/3

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Write a quadratic equation given the roots -1/3 and 5, show your work

Travka [436]

$\boxed{(x - a)(x - b) = 0}$

The equation above is the intercept form. Both a-term and b-term are the roots of equation.

$x = - \frac{1}{3} \\ x = 5$

These are the roots of equation. Therefore we substitute a = - 1/3 and b = 5 in the equation.

$(x + \frac{1}{3} )(x - 5) = 0$

Here we can convert the expression x+1/3 to this.

$x + \frac{1}{3} = 0 \\ 3x + 1 = 0$

Rewrite the equation.

$(3x + 1)(x - 5) = 0$

Simplify by multiplying both expressions.

$3 {x}^{2} - 15x + x - 5 = 0 \\ 3 {x}^{2} - 14x - 5 = 0$

Answer Check

Substitute the given roots in the equation.

$3 {(5)}^{2} - 14(5) - 5 = 0 \\ 75 - 70 - 5 = 0 \\ 75 - 75 = 0 \\ 0 = 0$

$3( - \frac{1}{3} )^{2} - 14( - \frac{1}{3}) - 5 = 0 \\ 3( \frac{1}{9} ) + \frac{14}{3} - 5 = 0 \\ \frac{1}{3} + \frac{14}{3} - \frac{15}{3} = 0 \\ \frac{15}{3} - \frac{15}{3} = 0 \\ 0 = 0$