by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
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which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
Example :
x y
1 3
2 6
3 9
4 12
first thing u do is pick any 2 points (x,y) from ur table
(1,3) and (2,6)
now we sub those into the slope formula (y2 - y1) / (x2 - x1) to find the slope
(y2 - y1) / (x2 - x1)
(1,3)....x1 = 1 and y1 = 3
(2,6)...x2 = 2 and y2 = 6
sub
slope = (6 - 3) / (2 - 1) = 3/1 = 3
now we use slope intercept formula y = mx + b
y = mx + b
slope(m) = 3
use any point off ur table...(1,3)...x = 1 and y = 3
now we sub and find b, the y int
3 = 3(1) + b
3 = 3 + b
3 - 3 = b
0 = b
so ur equation is : y = 3x + 0....which can be written as y = 3x...and if u sub any of ur points into this equation, they should make the equation true....if they dont, then it is not correct
and if u need it in standard form..
y = 3x
-3x + y = 0
3x - y = 0 ...this is standard form
3 x 6 x 9 x 3 x 6 x 9 = ?
3 x 6 = 18
18 x 9 = 162
162 x 3 = 486
486 x 6 = 2,916
2,916 x 9 = 26,244
3 x 6 x 9 x 3 x 6 x 9 = 26,244
Yes you take 3 times 4 and receive 12 and 5 times 4 and receive 20
