The answer to your question is 80 because 10 times 80 equals 800
Answer:
Area of the figure = 31.25π cm²
Perimeter of the figure = (12.5π + 10) cm
Step-by-step explanation:
Area of the given figure = Sum of area of the two semicircle + area of a quarter circle
Area of one quarter circle (CDE) =
=
= 6.25π
Area of one semicircle = 2 × Area of one quarter circle
= 2(6.25π)
= 12.5π
Area of the given figure = 2×12.5π + 6.25π
= 25π + 6.25π
= 31.25π cm²
Perimeter of the figure = Perimeter of two semicircles + perimeter of one quarter circle + measure of radius DE + measure of radius AB
Perimeter of one semicircle = πr
= 5π cm
Perimeter of one quarter circle = 2.5π
Perimeter of the complete figure = 10π + 2.5π + 5 + 5
= (12.5π + 10) cm
Answer:
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Step-by-step explanation:
Given
Required
Determine
We know that:
This gives:
Collect like terms
Take square roots
By tan identity
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Given:
Temperature in the morning = 6°F.
By the late afternoon, the temperature had dropped 9°F.
To find:
The temperature by the late afternoon.
Solution:
Temperature by the late afternoon = Morning temperature - Dropped temperature
Using the given values and the above formula, we get
Temperature by the late afternoon = 6°F - 9°F
Temperature by the late afternoon = -3°F
Therefore, the temperature by the late afternoon is -3°F.