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2 years ago

Write the equation of a circle with a center at (12, 6) and a radius of 6.

Mathematics

1 answer:

uranmaximum [27]2 years ago

3 0

Answer:

(x-12)² + (y-6)² = 36 (Option C)

Step-by-step explanation:

use circle formula

(x-h)² + (y-k)²= r²

h= 12 and k= 6 and r= 6

(x-12)² + (y-6)² = 6²

6 squared = 36 (6·6)

(x-12)² + (y-6)² = 36

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Sharad went to his friend's place on a motorcycle. When he started, the reading was 19,235 km. When he reached his friend's plac

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Answer:

the number of km did sharad travel is 66 km

Step-by-step explanation:

The computation of the number of km did sharad travel is as follows:

= The km at his friend place - km when he started

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= 66 km

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Hi there!

$\boxed{= 70 + cos(12) - cos(2) \approx 71.26}$

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$\int x^n = \frac{x^{n+1}}{n+1}$

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$\int -sin(x) = cos(x)$

Therefore:

$\int\limits^{12}_{2} {x-sin(x)} \, dx = [\frac{1}{2}x^{2}+cos(x)]_{2}^{12}$

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