Answer:
![\large\boxed{D.\ 2x^2y\sqrt[5]{7xy^3}}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7BD.%5C%202x%5E2y%5Csqrt%5B5%5D%7B7xy%5E3%7D%7D)
Step-by-step explanation:
![\sqrt[5]{224x^{11}y^8}\\\\=\sqrt[5]{(32)(7)x^{5+5+1}y^{5+3}}\\\\\text{use}\ a^na^m=a^{n+m}\\\\=\sqrt[5]{(2^5)(7)x^5x^5x^1y^5y^3}\\\\\text{use}\ \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\=\sqrt[5]{2^5}\cdot\sqrt[5]{x^5}\cdot\sqrt[5]{x^5}\cdot\sqrt[5]{y^5}\cdot\sqrt[5]{7xy^3}\\\\\text{use}\ \sqrt[n]{a^n}=a\\\\=2\cdot x\cdot x\cdot y\cdot\sqrt[5]{7xy^3}\\\\=2x^2y\sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B224x%5E%7B11%7Dy%5E8%7D%5C%5C%5C%5C%3D%5Csqrt%5B5%5D%7B%2832%29%287%29x%5E%7B5%2B5%2B1%7Dy%5E%7B5%2B3%7D%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5Ena%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%3D%5Csqrt%5B5%5D%7B%282%5E5%29%287%29x%5E5x%5E5x%5E1y%5E5y%5E3%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%5Ccdot%5Csqrt%5Bn%5D%7Bb%7D%5C%5C%5C%5C%3D%5Csqrt%5B5%5D%7B2%5E5%7D%5Ccdot%5Csqrt%5B5%5D%7Bx%5E5%7D%5Ccdot%5Csqrt%5B5%5D%7Bx%5E5%7D%5Ccdot%5Csqrt%5B5%5D%7By%5E5%7D%5Ccdot%5Csqrt%5B5%5D%7B7xy%5E3%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da%5C%5C%5C%5C%3D2%5Ccdot%20x%5Ccdot%20x%5Ccdot%20y%5Ccdot%5Csqrt%5B5%5D%7B7xy%5E3%7D%5C%5C%5C%5C%3D2x%5E2y%5Csqrt%5B5%5D%7B7xy%5E3%7D)
So 3 times the measure of a small angle
3x + x= 180
4x = 180
X= 45
3(45) + 4(45) = 180
Hope this helps!
The greatest common factor of 8x and 22yx is 2x.
I got this answer by factoring out 8 and 22:
8: 1,2,4,8
22: 1,2,11,22
Their greatest common factor was 2 and they both have x.
Your answer is 2x.
Hope this helped! :)
1000/7 = <span>142.857142857
Because this is not an even number we take "142", then times it by 7 teachers.
142*7= 994
1000 - 994 = 6 Pencils left</span>
