The normal to the plane is (Fx, Fy, Fz) = (1, 1, 8)
We have (x0, y0, z0) = (-1, - 6, 3)
Equation of the plane:
Fx(x - x0) + Fy(y - y0) + Fz(z - z0) = 0
=> (1)(x + 1) + (1)(y + 6) + (8)(z - 3) = 0
=> x + 1 + y + 6 + 8z - 24 = 0
=> x + y + 8z = 17
Answer:
Explanation:
The question in english is:
A ray of light falls under an angle of incidence of 30 degrees on a flat surface that separates two transparent materials with indexes of refractions 1.60 and 1.40, respectively.
Calculate the angle of refraction (from the environment with the lower index of refraction)
<u>Solution</u>
According to Snell's Law :
Where:
is the first medium index of refraction
is the second medium index of refraction
is the angle of the incident ray
is the angle of the refracted ray
We need to find from the equation above,
<h2>Therefore, the angle of refraction is 34.84°</h2>
<span>it fairly is going to attain a speed of 24 m/s in a 2d, yet between t = 0 and t = a million, it fairly is not any longer vacationing at that speed, yet at slower speeds. it fairly is 12 meters. ?D = [ ( a?T^2 + 2?Tv_i ) ] / 2 the place: ?D = displacement a = acceleration ?T = elapsed time v_i = preliminary speed ?D = [ ( 24m/s^2 • 1s • 1s + 2 • 1s • 0m/s ) ] / 2 ?D = 24 / 2 ?D = 12m</span>