If 3 points and pi is 3.14 that would have to be equal to 6t
Answer:
3^4, she raised it to the 4th power
Step-by-step explanation:
3^x+19=100
-19
3^x=81
We can make a table now to find what power of three = 81
Powers of three table
3^1=3 3^2=9 3^3=27 3^4=81
<span>f(x)=3[x-2]
So, f(5.9) = ?
f(5.9) = 3(5.9 - 2)
=3(3.9)
=11.7 = 12
Thus, the answer is 12.
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Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
P = 4r + 3t
4r = p - 3t
r = (p - 3t)/4
