Consider U = {x|x is a real number}.
2 answers:
Answer:
Option c.
Step-by-step explanation:
We have the set of real numbers greater than 8 and B the set of real numbers greater than 5 here:
A: x+2>10 ⇒ x>8
B: 2x > 10 ⇒ x>5
8∉A ; 8∈B
Note: We can see (graph) that the intervals are open, so the corresponding points do not belong to their respective sets.
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Answer:
x = i and x = i
Step-by-step explanation:
Given
+ 6x² + 5 = 0
Using the substitution u = x², then
u² + 6u + 5 = 0 ← in standard form
(u + 1)(u + 5) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 1 = 0 ⇒ u = - 1
u + 5 = 0 ⇒ u = - 5
Convert solutions back into terms of x
x² = - 1 ⇒ x = = i
x² = - 5 ⇒ x = = i