Answer:
The digit '0' is in the ones place.
25% of people leave early as 6 is 1/4 of 24. You can solve this by dividing 6 by 24 (I believe, maybe check with someone on that but that’s how i figured it out).
Hey there!!
Fill in the blanks :-
⇒ First graph the line. Locate the <u>value of x </u>on the x-axis. Draw a vertical line from <u>point plotted on the x-axis </u>to the graph of the function and a horizontal line segment from the graph of the function to the y-axis.
<em>Find the value of f(x) when x is -2. </em>
Remember :- <u><em>f(x) is basically the y-value. It is just denoted as _f(x), it stands for function of x. Which means, the value of y, depends upon the value of x or the function of x. </em></u>
Given : x = - 2
Plugging in the values :
... 
... 
... 
The last fill in the blank :
The value of y on the y-axis is the value of the function. Therefore, the value of f(x) is <u>-7 </u>when x is -2.
Hope it helps!!
I believe the answer should be 77
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
