Answer:
102000 kg
Explanation:
Given:
A total Δν = 15 km/s
first stage mass = 1000 tonnes
specific impulse of liquid rocket = 300 s
Mass flow rate of liquid fuel = 1500 kg/s
specific impulse of solid fuel = 250 s
Mass flow of solid fuel = 200 kg/s
First stage burn time = 1 minute = 1 × 60 seconds = 60 seconds
Now,
Mass flow of liquid fuel in 1 minute = Mass flow rate × Burn time
or
Mass flow of liquid fuel in 1 minute = 1500 × 60 = 90000 kg
Also,
Mass flow of solid fuel in 1 minute = Mass flow rate × Burn time
or
Mass flow of solid fuel in 1 minute = 200 × 60 = 12000 kg
Therefore,
The total jettisoned mass flow of the fuel in first stage
= 90000 kg + 12000 kg
= 102000 kg
Answer:
You would have to find the friction force of the rubber block which would be found with the equation of Normal force (mass*gravity) times cooeficient of friction which would give 8.82 N for the amount of friction and because you need more force than 8.82 N (assuming gravity is 9.8)
Answer:
Given:
Mass of the polar bear (m) = 6.8 kg
Speed of the polar bear (v) = 5.0 m/s
To Find:
Kinetic energy of the polar bear (KE)
Explanation:
Formula:
Substituting values of m & v in the equation:
Kinetic energy of the polar bear (KE) = 23002.1 J
Answer:
(A). The flux is 0.336 N.m²/C
(B). The flux is zero.
Explanation:
Given that,
Length = 4.2 cm
Width = 4.0 cm
Electric field
Area vector is perpendicular to xy plane
(A). We need to calculate the flux
Using formula of flux
Where, E = electric field
A = area
Put the value into the formula
(B). Given electric field
We need to calculate the flux
Using formula of flux
Put the value into the formula
Here, The component of k is not given
So, the flux is
Hence, (A). The flux is -0.336 N.m²/C
(B). The flux is zero.
Answer:
1) Weight on Mercury
Explanation:
do the same to the rest and use your calculator to find the weight in N.