PLEASE HURRY WILL MARK BRAINLIEST IF CORRECT

In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.2 m. The mug s

ZanzabumX [31]

Part a can be solve using the equation of trajectory:

Y = x tana + (g*x^2)/ [2(V0^2)*(cos a)^2]

Where y is the height

X is the length

G is the acceleration due to gravity

Vo Is the initail velocity

a is the angle of trajectory

1.2 = 1.35 tan(0) + (9.81*1.35^2)/ [2(V0^2)*(cos 0)^2]

Solve for V0 = 2.729 m/s

b. can be solve using the formula

v = sqrt(2gy)

= sqrt ( 2*1.2*9.81)

= 4.852 m/s going down ( 0 degree from the horizontal)

6 0

2 years ago

Heat likes to remain ONMFRIU ← Whats that unscrambled?

OlgaM077 [116]

So the question is how does heat prefer to remain and to unscramble the letters ONMFRIU. The unscrambled letters mean: UNIFORM. The heat likes to remain uniform because thermodynamic systems always tend to reach thermal equilybrium after some period of time that is specific for each system.

5 0

2 years ago

Why does the output of a microphone increase as the frequency of the sound waves which it receives increases

Sloan [31]

Answer:

See Explanation

Explanation:

The frequency of sound waves received by the microphone influences the output or pitch of the sound obtained from the microphone.

The higher the frequency of the sound received by the microphone, the higher the output of the microphone and vice versa. This is because, the higher the frequency of sound, the higher the oscillations produced and the greater the output of the microphone.

The rise and fall in the pitch of sound waves as the frequency of sound waves varies is called inflection.

7 0

2 years ago

A rocket sled with an initial mass of 3 metric tons, invluding 1 ton of fuel, rests on a level section of track. At t=0, the sol

ELEN [110]

Answer:

v = 719.2 m / s and a = 83.33 m / s²

Explanation:

This is a rocket propulsion system where the system is made up of the rocket plus the ejected mass, where the final velocity is

v - v₀ = $v_{e}$ ln (M₀ / M)

where v₀ is the initial velocity, v_{e} the velocity of the gases with respect to the rocket and M₀ and M the initial and final masses of the rocket

In this case, if fuel burns at 75 kg / s, we can calculate the fuel burned for the 10 s

m_fuel = 75 10

m_fuel = 750 kg

As the rocket initially had a mass of 3000 kg including 1000 kg of fuel, there are still 250 kg, so the mass of the rocket minus the fuel burned is

M = 3000 -750 = 2250 kg

let's calculate

v - 0 = 2500 ln (3000/2250)

v = 719.2 m / s

To calculate the acceleration, let's use the concept of the rocket thrust, which is the force of the gases on it. In the case of the rocket, it is

Push = v_{e} dM / dt

let's calculate

Push = 2500 75

Push = 187500 N

If we use Newton's second law

F = m a

a = F / m

let's calculate

a = 187500/2250

a = 83.33 m / s²

7 0

2 years ago

When a moving car is brought to a stop with the brakes, its acceleration vector is 29. (a) in the same direction as its velocity

professor190 [17]

To develop this problem we will apply the concepts related to the kinematic equations of motion, specifically that of acceleration. Acceleration can be defined as the change of speed in an instant of time, mathematically this is

$\vec{a} = \frac{\vec{v_2}-\vec{v_1}}{\Delta t}$

If a mobile is decreasing its speed (it is slowing down), then its acceleration is in the opposite direction to the movement. This would imply that the acceleration vector is opposite to the velocity vector.

Therefore the correct answer is B.

7 0

2 years ago