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2 years ago

Is the order pair (2,1) a solution to the equation 4x-2y=5?

Mathematics

1 answer:

torisob [31]2 years ago

6 0

No.

When you insert the numbers you get 8-2=5

This is inaccurate.

Please vote brainliest!

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Solve for X

tigry1 [53]

Answer:

$x = \pm e^{-1}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Algebra I

Solving quadratics
Multiple roots

Algebra II

Logarithms
Euler's number e

Step-by-step explanation:

Step 1: Define

$\displaystyle ln(x^2) = -2$

Step 2: Solve for x

Raise both sides by e: $e^{\displaystyle ln(x^2)} = e^{-2}$
Simplify equation: $x^2 = e^{-2}$
Square root both sides: $x = \pm e^{-1}$

7 0

2 years ago

Read 2 more answers

Mom is getting food ready for my birthday party! including me, there will be 24 people at the party. Mom is baking cupcakes for

Brilliant_brown [7]

You should tell your mom to bake 8 cupcake batches

7 0

1 year ago

21 times 9 equals 9 times 21 what is the property

Reil [10]

Commutative property....

5 0

2 years ago

Xavier, Yessie, and Zorro each choose a different favorite positive fraction. Each fraction is in simplest form. Yessie's fracti

ad-work [718]

Let Xavier's favourite fraction be a/b, Yessie's favourite fraction = b/a and Zorro's favourite fraction = c/d,

c/d x a/b = 12/35 . . . . . . . . (1)
c/d x b/a = 15/7 . . . . . . . . (2)

(1) x (2) = c/d x a/b x c/d x b/a = 12/35 x 15/7
c^2 / d^2 = 36/49
c^2 = 36
c = 6
d^2 = 49
d = 7

Xaviers favourite fraction = 12/35 / 6/7 = 2/5
Yessies favourite fraction = 5/2
Zorro favourite fraction = 6/7

8 0

2 years ago

4(3x^2y^4)^3 / (2x^3y^5)^4

tatyana61 [14]

Solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$