When there is a midpoint in a line segment, the two segments that are then produced have to be equal. So that means that because E is a midpoint of DF, DE=EF.
Set up the equation.
DE=EF
2x+4=3x+1
Then solve for x.
x=3
Then plug it back in the equation to find DE and EF.
DE=2x+4=2(3)+4=10
Because DE=EF then EF is also 10.
DF is made from the addition of DE and EF so DF is twice EF.
DF= 20
DE= 10, EF= 10, DF= 20
Hope this helps.
Q11
Suppose the two numbers are x and y so xy = 3000
the HCF = 10
we know that product of two numbers = product of their HCF and LCM
XY = HCF * LCM
3000 = 10 * LCM
3000/10 = LCM
300 = LCM
Answer 300
Q12 : Let us say second number is x so
product of x and 160 = product of HCF and LCM of ( x and 160 )
160 x = 32 * 1760
x= 32 * 1760 / 160
x= 352
Answer : 352
Answer: 2 nickels
Rachel has 20 coins composed of nickles, dimes and quarters
amounting to $3.70. Her quarters are twice the number of her dimes, the number
of nickels can be computed as follows:
If X= the number of
dimes at .10 each
Then 2x= the number
of quarters at .25 each and
20-(X-2X)= the number of nickels at .05 each
<span>
<span><span>
<span>
The equation will be:
X(.1)+2(X).25+(20-X-2X).10=3.70
</span>
</span>
<span>
</span>
<span>
<span>
.1X+2X(.25)+(20-X-2X).05=3.70
</span>
</span>
<span>
<span>
.1X+.5X+(20-3X).05=3.70
</span>
</span>
<span>
<span>
.6X+(1-.15X)=3.70
</span>
</span>
<span>
<span>
.6X+1-.15X=3.70
</span>
</span>
<span>
<span>
.45X=3.70-1
</span>
</span>
<span>
<span>
.45X=2.70
</span>
</span>
<span>
<span>
X=2.70/.45
</span>
</span>
<span>
<span>
X=6 number of dimes
</span>
</span>
<span>
<span>
2X=12 number of quarters
</span>
</span>
<span>
<span>
20-6-12=2 number of nickels
</span>
</span>
</span></span>
Answer:
2/3
Step-by-step explanation:
Total sides = 6
Number 5 and all even numbers = 1+3
=> 4
P(5 or even ) = 4/6
=> 2/3
I don’t think you attached a picture along sigh the question, i don’t see any graphs shown
