Explanation:
When the covalent bonds in a molecule are polarized so that one portion of the molecule experiences a positive charge and the other portion of the molecule experiences a negative charge. This separation of opposite charges creates an electric dipole.
Answer:
- <u>two molecules of ammonia are formed by the reaction of one nitrogen and three hydrogen molecules.</u>
Explanation:
The balanced chemical equation provides information on:
- <u>Reactants</u>: those are the compounds that appear of the left side of the equation, each with its chemical formula.
- <u>Products</u>: those are the compounds that appear on the right side of the equation, again, each with its chemical formula.
- <u>Ratio</u>: the coefficients of each compound (the number to the left of the chemical formula) represent the ratio of the number of molecules that react and are formed.
In the given equation you have:
- Equation: N₂ + 3H₂ → 2NH₃
- The coefficients are 1 for nitrogen, 3 for hydrogen, and 2 for ammonia. Hence, 2 molecules of ammonia are formed by the reaction of 1 molecule of nitrogen and 3 molecules of hydrogen.
It is water soluble so is also soluble in aqueous solutions of NaOH or NaHCO3.
Answer:
The enthalpy of the solution is -35.9 kJ/mol
Explanation:
<u>Step 1:</u> Data given
Mass of lithiumchloride = 3.00 grams
Volume of water = 100 mL
Change in temperature = 6.09 °C
<u>Step 2:</u> Calculate mass of water
Mass of water = 1g/mL * 100 mL = 100 grams
<u>Step 3:</u> Calculate heat
q = m*c*ΔT
with m = the mass of water = 100 grams
with c = the heat capacity = 4.184 J/g°C
with ΔT = the chgange in temperature = 6.09 °C
q = 100 grams * 4.184 J/g°C * 6.09 °C
q =2548.1 J
<u>Step 4:</u> Calculate moles lithiumchloride
Moles LiCl = mass LiCl / Molar mass LiCl
Moles LiCl = 3 grams / 42.394 g/mol
Moles LiCl = 0.071 moles
<u>Step 5:</u> Calculate enthalpy of solution
ΔH = 2548.1 J /0.071 moles
ΔH = 35888.7 J/mol = 35.9 kJ/mol (negative because it's exothermic)
The enthalpy of the solution is -35.9 kJ/mol
