The answer is the 1st one
In order to figure this out you need to use slope intercept for for each of these hills. Let's say the first hill is HA and the second hill is B
slope intercept: y = mx + b
HA: y = (2/10)x
HB: y = (2/15)x
As you can see when you plot this on a graph, HB is steeper because the line rises more sharply.
Answer:
B
Step-by-step explanation:
Let point N has coordinates (0,0), then figure A has vertices at points (-3,0), (-7,0), (-7,4) and (-3,4). Figure B has vertices at points (3,1), (7,1), (7,-3) and (3,-3).
1. Translation 10 units to the right has the rule
(x,y)→(x+10,y).
Then vertices of the figure A have images:
- (-3,0)→(7,0);
- (-7,0)→(3,0);
- (-7,4)→(3,4);
- (-3,4)→(7,4).
2. Translation 3 units down has the rule
(x,y)→(x,y-3).
Then images are
- (7,0)→(7,-3);
- (3,0)→(3,-3);
- (3,4)→(3,1);
- (7,4)→(7,1).
As you can see these points are exactly the vertices of the figure B.
