We used the elimination method to find the ordered pair, (x,y), that represents the situation is (12,39).
Number of invoices = 51
Charge for tree installation = $375
Charge for tree trimming = $54
Total amount in invoices = $6,606
Let x and y represent number of installations and number of trimmings respectively.
Hence,
x + y = 51 ...(1)
375x + 54y = 6606
3 (125x + 18y) = 3*2202
125x + 18y = 2202 ...(2)
Multiplying (1) by 18, we get
18x + 18y = 918 ...(3)
(2) - (3)
107x + 0 = 1284
x = 1284/107 = 12
Hence,
y = 51 - 12 = 39.
To learn more about elimination method, here:-
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36. If 7/11 did bring one, then 4/11 didn't. 4*9=36
n = 2
distribute and simplify left side of equation
50 - 10n - 1 = 29
49 - 10n = 29 ( subtract 49 from both sides )
- 10n = 29 - 49 = - 20
n = = 2
Answer:
And using this formula we have this:
Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917
Step-by-step explanation:
Let X the random variable of interest that a woman must wait for a cab"the amount of time in minutes " and we know that the distribution for this random variable is given by:
And we want to find the following probability:
And for this case we can use the cumulative distribution function given by:
And using this formula we have this:
Then we can conclude that the probability that that a person waits fewer than 11 minutes is approximately 0.917
Answer:
20 comic books
Step-by-step explanation:
Let us first <u>set up a variable</u>, x, for the number of books that Zoe has. If Jared has 12 more comics than Zoe, he would have x+12 books.
Given that Zoe and Jared have a total of 28 comic books, let us write an <u>equation</u> and solve for x:
Now that we have a <u>simplified</u> version of the equation, let us solve for x by <u>isolating the variable</u> on the left side:
We now know that x=8, and also that Jared has x+12 books. To find the number of comic books Jared has, let us <u>add</u> 12 to x:
Therefore, Jared has 20 comic books.
<em>I hope this helps! Please let me know if you have any further questions :)</em>