Let's say the amount of nickels you have is hmm "n"
and the amount of dimes you have is "d"
there are 5cents in one nickel, so, if "n" is the total amount of nickels you have, that means 5 * n cents or 5n
there are 10cents in one dime, so, if "d" is the total amount of dimes you have, that means 10*d or 10d
whatever 5n and 10d are, we know that their sum is 595
since the total amount the counter said you have is, only 595 cents
thus 5n + 10d = 595
solve for either, "d" or "n", and graph that
what are three likely combinations? well, just pick three points off that graph
Answer:
35.4%
Step-by-step explanation:
(100/80) x 27.6
basically 1 of 80 is 1.25 and multiply 1.25 times the money jaylon spent sorry i am really bad at explaining only good at solving
Answer:(X^2-11)(2X-5)
Step-by-step explanation:
2x^3-5x^2-22x+55
x^2(2x-5)-11(2x-5)
(X^2-11)(2X-5)
Answer:
6:1:2
Step-by-step explanation:
Let a = Able's score, b = Ben's score, and c = Cal's score.
Since
Able's score was 6 times Ben's score, that means a = 6b.
Cal's score was a third of Able's score, so that means c = a/3. And since a = 6b, that means c = 6b / 3 = 2b.
Thus, the ratio of Able's score to Ben's score to Cal's score, a:b:c, is 6:1:2, because c is twice as much as b and a is 6 times as much as b.
