Let
a---------> length of one of the two congruent sides of the triangle
we know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
so
(a+a) > 8
2a > 8
a> 4
Rounded to the nearest tenth, <span>the smallest possible length of a is 4.1
</span>
the answer is
4.1 units
Answer:
x = 14
Step-by-step explanation:
→ Set up an equation
4x + 15 + 39 = 110
→ Simplify
4x + 54 = 110
→ Minus 54 from both sides
4x = 56
→ Divide both sides by 3
x = 14
Answer:
23 sin 55°
x = ------------------ (matches first answer choice)
sin 85°
Step-by-step explanation:
Note that 2 angles and 1 side length are given. This is a typical application of the Law of Sines. The formula for finding the length of side x is:
23 sin 55°
x = ------------------ (matches first answer choice)
sin 85°
easiest thing to do is combine like terms. There are 9 2's, which means 9(2) which equals 18. Now for the X's. There are 9 X's meaning (9)x which is 9x. This all makes up
18+9x
hope this helps
Answer:
x=3/7 and x= 3
Step-by-step explanation:
First simplify:
-14 x^2 +48x -18
divide everything by -2
-2(7 x^2 -24x +9) (Multiply the leading coefficient 7 by the constant 9)
-2 (x^2 -24x +63)
-2 [(x-3)(x-21)] Now divide the 7 that you multiplied earlier from 3 and 21
-2 [(x-3/7)(x-21/7)]
-2 [(7x-3)(x-3)]
Hence, the zeroes are 3/7 and 3
Hope this helps!
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