Answer:
Accelerate up more compressed spring
Accelerate down spring less compressed
Explanation:
For this problem we must analyze the forces that act on the scale on the one hand the weight of the man directed downwards and I have the other the elastic force of the spring directed upwards. Now let's write Newton's second law for these forces in various configurations,
When the elevator is quiet or moving at constant speed
Fe - W = 0 ⇒ Fe = W -k x = mg x = mg /k
Fe = mg
We use this value to compare
Now let's analyze when the elevator accelerates upwards
Fe -W = m a
Fe = ma + W
Fe = m (a + g)
So we can see that Fe increases, so the compression of springs is higher
Now let's analyze when the elevator acceleration is down
Fe -W = m (-a)
Fe = w - m a
Fe = m (g -a)
In this case Fe is smaller, so the compression of the spring is less