Answer:
793.25 mi/hr
Step-by-step explanation:
Given that:
The radius of the earth is = 3030 miles
The angular velocity =
If a jet flies due west with the same angular velocity relative to the ground at the equinox;
We are to determine the How fast in miles per hour would the jet have to travel west at the 40th parallel for this to happen.
NOW;
Distance s is expressed by the relation
s = rθ
s = 793.25
The speed which depicts how fast in miles per hour the jet would have traveled is :
v = 793.25 mi/hr
Hence, the jet would have traveled 793.25 mi/hr due west at the 40th parallel for this to happen.
12x^3-11x^2+9x+18 divided by 4x+3
put he division into fraction
12x^3-11x^2+9x+18/4 x +3
reduced fraction by 2
12x^3-11x^2+9x+9/2 x +3
calculate sum
12x^3-11x^2+27/2 x +3
that is your answer ^
hope this helps :)
Answer:
<FEA is 70 degrees. It is already given.