<h2><u>DIRECT RULE OF 3</u></h2>
We use a rule of 3 to solve it.
Let's record the data:
253 miles → 8 hours
x miles → 7 hours
Let's solve:
<h3><u>Answer</u>. The car can travel 221,375 miles in seven hours.</h3>
Hello from MrBillDoesMath!
Answer: 2
Description. Create a line from point A perpendicular to the x axis. This line, with the radius (OA) , and x axis, form a right triangle. By Pythagoras,
x-length y-length hypotenuse squared
( 3 ^ (1/2) ) ^ 2 + 1 ^ 2 = 3 + 1 = 4
So, the square of the hypotenuse (or radius OA in this case) is 4. That means OA is the square root of 4 or 2.
Regards, MrB
Answer:
t=0.64
Step-by-step explanation:
h = -16t^2 +4t +4
We want h =0 since it is hitting the ground
0 = -16t^2 +4t +4
Using the quadratic formula
a = -16 b = 4 c=4
-b ± sqrt( b^2 -4ac)
----------------------------
2a
-4 ± sqrt( 4^2 -4(-16)4)
----------------------------
2(-16)
-4 ± sqrt( 16+ 256)
----------------------------
-32
-4 ± sqrt( 272)
----------------------------
-32
-4 ± sqrt( 16*17)
----------------------------
-32
-4 ± sqrt( 16) sqrt(17)
----------------------------
-32
-4 ± 4 sqrt(17)
----------------------------
-32
Divide by -4
1 ± sqrt(17)
----------------------------
8
To the nearest hundredth
t=-0.39
t=0.64
Since time cannot be negative
t=0.64
Answer:
Step-by-step explanation:
The space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.
<h3>What is a cone?</h3>
It is defined as the three-dimensional shape in which the base is a circular shape and if we go from circular base to top the diameter of the circle reduces and at the vertex, it becomes almost zero.
We know the volume of the cylinder is given:
r = 10/2 = 5 FT
h = 12 FT
V = 300π cubic FT
Volume of the cone:
v = 100π cubic FT
Space is inside the cylinder but outside the cone = 300π - 100π
= 200π cubic FT
= 628.32 cubic FT
Thus, the space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.
Learn more about the cone here:
brainly.com/question/16394302
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