Answer:
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Explanation:
Answer:
distance when the weight is 8 kg is 26.66 cm
Explanation:
given data
distance d2 = 10 cm
weight w2 = 3 kg
weight w1 = 8 kg
to find out
distance when the weight is 8 kg
solution
we consider here distance d1 when weight is 8 kg
so equation will be
d1/d2 = w1/w2
d/10 = 8/ 3
so d = 8/3 × 10
so d = 26.66
distance when the weight is 8 kg is 26.66 cm
The power of man performing 500 J of work in 8 seconds is 62.5 J/s.
Power can be defined as the pace at which work is completed in a given amount of time.
Horsepower is sometimes used to describe the power of motor vehicles and other machinery.
The pace at which work is done on an item is defined as its power. Power is a temporal quantity.
Which is connected to how quickly a project is completed.
The power formula is shown below.
Power = Energy / Time
Power = E / T
Because the standard metric unit for labour is the Joule and the standard metric unit for time is the second, the standard metric unit for power is a Joule / second, defined as a Watt and abbreviated W.
Here we have given Energy as 500 J and Time as 8 second.
Power = Energy / Time
Power = 500 / 8 Joule / sec
Power = 250 / 4 Joule / sec
Power = 125 / 2 Joule / sec
Power = 62.5 Joule / sec or 62.5 watt
Power came out to be 62.5 J/s when the man performed 500 Joule of work in 8 seconds.
So we can conclude that the power in the Energy transmitted per unit of time, and can be find out by dividing Energy by time. In our case the Power came out to be 62.5 Joule / Second.
Learn more about Power here:
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Answer:
Relative to Sir George's starting point, the knights collide at a distance of 38.43 m from Sir George's starting point.
Explanation:
Let the distance covered by Sir George be
and the distance covered by Sir Alfred be
Since the knights collide, hence they must have traveled for the same amount of time just before collision
From one of the equations of motion for linear motion
Where is the distance traveled
is the initial velocity
is the acceleration
and is the time
For Sir George,
= 0 m/s (Since they start from rest)
0.21 m/s²
Hence,
becomes
Now, for Sir Alfred
= 0 m/s (Since they start from rest)
0.26 m/s²
Hence,
becomes
Since, they traveled for the same time, just before collision, we can write
Since, the two nights are 86 m apart, that is, the sum of the distances covered by the knights just before collision is 86 m. Then we can write that
m
Then,
Then,
becomes
m
∴ Sir George covered a distance of 38.43 m just before collision.
Hence, relative to Sir George's starting point, the knights collide at a distance of 38.43 m from Sir George's starting point.
Answer:
Diorite, Gabbro, and Granite
Explanation: