The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
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Answer:
Your answer would be A: "college savings account."
Step-by-step explanation:
Got it right on edge.
Answer:
B
Step-by-step explanation:
The compound interest formula is 
where:
- P is the starting amount called the principle
- r is the rat written as a decimal
- n is the number of times compounded in a year
- t is the number of years
Substitute a value into each variable to solve.
- P = $147 since 10% of 1,470 is being invested which makes P = 0.10(1470) = 147.
- The rate is 3.5% or r = 0.035.
- n = 12 because it is compounded monthly meaning 12 times a year.
- t = 25 since it will earn for 25 years.
Repeat this process for each formula.
Answer:
Your answer is (D)-7
Step-by-step explanation:
