Answer:
v = -1.8t+36
20 seconds
360 m
40 seconds
36 m/s
The object speed will increase when it is coming down from its highest height.
Explanation:
Differentiating with respect to time we get
a) Velocity of the object after t seconds is v = -1.8t+36
At the highest point v will be 0
b) The object will reach the highest point after 20 seconds
c) Highest point the object will reach is 360 m
d) Time taken to strike the ground would be 20+20 = 40 seconds
Acceleration will be taken as positive because the object is going down. Hence, the sign changes. 2 is multiplied because the expression is given in the form of
e) The velocity with which the object strikes the ground will be 36 m/s
f) The speed will increase when the object has gone up and for 20 seconds and falls down for 20 seconds. The object speed will increase when it is coming down from its highest height.
Gravitational energy is a form of potential energy because it is dependent on the mass of an object and needs to be calculated for the specific object.
A research question that would complete the third question you need that are related to the first 2 questions which are:
- “what type of masks help prevent fog on glasses when breathing?”
- “does a mask’s material affect the level of fog on glasses as an effect of breathing?”
Would be: "Are there any available masks that could prevent fog on glasses that could be improved upon"?
This new research question would help you find out if there is an already existing mask that could be made better.
<h3>What is a Research Question?</h3>
This refers to "a question that a research project sets out to answer". and seeks to give answers to particular phenomena.
Hence, we can see that the new research question Would be: "Are there any available masks that could prevent fog on glasses that could be improved upon"?
This new research question would help you find out if there is an already existing mask that could be made better.
Read more about research questions here:
brainly.com/question/25257437
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Speed = (frequency)x(wavelength).
Frequency = 6 Hz
Wavelength = 9mm = 0.009m.
Speed = (6 Hz) x (0.009m) = 0.054 m/s or 54 mm/sec.
Answer:
Final velocity of the block = 2.40 m/s east.
Explanation:
Here momentum is conserved.
Initial momentum = Final momentum
Mass of bullet = 0.0140 kg
Consider east as positive.
Initial velocity of bullet = 205 m/s
Mass of Block = 1.8 kg
Initial velocity of block = 0 m/s
Initial momentum = 0.014 x 205 + 1.8 x 0 = 2.87 kg m/s
Final velocity of bullet = -103 m/s
We need to find final velocity of the block( u )
Final momentum = 0.014 x -103+ 1.8 x u = -1.442 + 1.8 u
We have
2.87 = -1.442 + 1.8 u
u = 2.40 m/s
Final velocity of the block = 2.40 m/s east.