Answer:
Step-by-step explanation:
\mathrm{Multiply\:the\:numerator\:and\:denominator\:by:}\:100
\mathrm{Multiply\:the\:quotient\:digit}\:\left(0\right)\:\mathrm{by\:the\:divisor}\:505
\mathrm{Subtract}\:0\:\mathrm{from}\:23
We know that the amounts earned by Dawn, Doug and Dale are from the list of numbers: $9.35, $8.52 and $8.25
We also know that Dale and Doug earned close to $9.00
And that Dawn earned $1.10 less than Dale
Let the amount earned by Dale be x
⇒ Amount earned by Dawn is x - 1.1
If we notice the list of numbers, we see that $9.35 and $8.25 differ by $1.1
Hence, Dale earned $9.35 and Dawn earned $8.25
We are now left with $8.52, which should be the amount earned by Doug. This is correct, since we also know that Doug earned close to $9.
Hence, the amounts earned are:
Dale: $9.35
Doug: $8.52
Dawn: $8.25
Answer:
[-5, 4) ∪ (4, ∞)
Step-by-step explanation:
Given functions:
Composite function:
Domain: input values (x-values)
For to be defined:
Therefore, and
⇒ [-5, 4) ∪ (4, ∞)
Answer:
I found two different solutions. Hope one of them help!
1. x = -1/3 = -0.333
2. x = 5/2 = 2.500
Step-by-step explanation:
13 ± √ 289
x = ——————
12
Can √ 289 be simplified ?
Yes! The prime factorization of 289 is
17•17
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 289 = √ 17•17 =
± 17 • √ 1 =
± 17
So now we are looking at:
x = ( 13 ± 17) / 12
Two real solutions:
x =(13+√289)/12=(13+17)/12= 2.500
or
x =(13-√289)/12=(13-17)/12= -0.333
Two solutions were found :
x = -1/3 = -0.333
x = 5/2 = 2.500
Answers:
T-shirt = $25
Shorts = $15
Books = $50
Shoes = $30
Cell phones = $750
===============================================
Explanation:
Taking 10% of a number is simply moving the decimal point over one spot to the left.
For example, the selling price of a t-shirt is $250.00 and taking 10% of this gets us to $25.00
As another example, 10% of 150.0 is 15.0
If a whole number ends with a 0, then taking 10% of the number means we chop that zero off.