Answer:
D. 77 + 8
Step-by-step explanation:
7 x 8 = 56
now try the other problems
A. 6 x 8 = 48
B. 6 x 7 = 42
C. 7 x 7 = 49
D. 77 + 8 = 56
D is the answer
Answer:
The sum of an even number plus an odd number is odd.
Step-by-step explanation:
The sum of an even number and an odd number is odd.
For example:
2+3=5
11+10=21
51+32=83
The end digit of an even number is always 0, 2, 4, 6, or 8
The end digit of an odd number is 1, 3, 5, 7, or 9.
So if we add only the end digit of an even and an odd number we can find no combination that can give end digit 0, 2, 4, 6, or 8(i.e even).
Hence, the sum of an even number plus an odd number is odd.
The cosine of an angle is the x-coordinate of the point where its terminal ray intersects the unit circle. So, we can draw a line at x=-1/2 and see where it intersects the unit circle. That will tell us possible values of θ/2.
We find that vertical line intersects the unit circle at points where the rays make an angle of ±120° with the positive x-axis. If you consider only positive angles, these angles are 120° = 2π/3 radians, or 240° = 4π/3 radians. Since these are values of θ/2, the corresponding values of θ are double these values.
a) The cosine values repeat every 2π, so the general form of the smallest angle will be
... θ = 2(2π/3 + 2kπ) = 4π/3 + 4kπ
b) Similarly, the values repeat for the larger angle every 2π, so the general form of that is
... θ = 2(4π/3 + 2kπ) = 8π/3 + 4kπ
c) Using these expressions with k=0, 1, 2, we get
... θ = {4π/3, 8π/3, 16π/3, 20π/3, 28π/3, 32π/3}
5y+2x=10y=−25x+2246810−2−4−6−8−10246810−2−4−6−8−10Let's solve for x.5y+2x=10Step 1: Add -5y to both sides.2x+5y+−5y=10+−5y2x=−5y+10Step 2: Divide both sides by 2.2x2=−5y+102x=−52y+5Answer:x=−52y+5
Answer:a is 52 b is 65
Step-by-step explanation:
a:Write 65% as 65100.
65100 of 80 = 65100 × 80.
Therefore, the answer is 52. If you are using a calculator, simply enter 65÷100×80 which will give you 52 as the answer.
b: it is 65 because it is the same question but in reverse which still gives you the same answer.
Hope this helps
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