Answer:
B. 1/6 m/s
Explanation:
Parameters given:
Mass of first glider, m = 1 kg
Initial speed of first glider, u = 1 m/s
Mass of second glider, M = 5 kg
Initial speed of second glider, U = 0 m/s.
Using the principle of conservation of momentum, we have that:
Total initial momentum = Total final momentum
=> m*u + M*U = m*v + M*V
Where v is the final velocity of the first glider and V is the final velocity of the second glider.
Since they stick upon collision, their final velocities are the same, hence, v = V
m*u + M*U = m*v + M*v
m*u + M*U = (m + M)*v
Also, since the second glider is initially at rest, U = 0
m*u = (m + M)*v
Therefore,
v = (m*u) / (m + M)
v = (1 * 1) / (1 + 5)
v = 1/6 m/s