Explanation:
To balance this chemical equation-
see
Balanced form:-
CaO + 2 HCl ==. CaCl2 + H2O
.
PH is the test of acidity or basicity of a solution. it follows the formula:
pH = pKa + log [salt] / [acid] where NaF is the salt and HF is the acid in this case.
By literature, Ka of HF is 3.5*10^-4
<span>pKa= -log(Ka)=</span><span> 3.46 </span>
<span>pH = pKa + log [NaF / [HF] </span>
4.05 = 3.46 + log [NaF / [HF]
log [NaF / [HF]<span> = 0.59
</span>
[NaF / [HF] = 3.89
The molecular formula of sucrose is - C₁₂H₂₂O₁₁
molecular mass of sucrose - 342 g/mol
molarity of sucrose solution is 0.758 M
In 1 L solution the number of sucrose moles are - 0.758 mol
Therefore in 1.55 L solution, sucrose moles are - 0.758 mol/L x 1.55 L
= 1.17 mol
The mass of 1.17 mol of sucrose is - 1.17 mol x 342 g/mol = 4.00 x 10² g
Answer:
Litre (L) , Centimetre (cm) , Kilogram (Kg), Seconds (s) and Kelvin (K)
Explanation:
The units are used for the following measurement;
Litre = Volume
Centimetre = Length
Kilogram = Mass
Seconds = Time
Kelvin = Temperature