Answer: ΔG =23.169kJ/mol
Explanation:
Solution
To Calculate Gibbs free energy ΔG for the reaction above we use the equation ΔG=ΔH−TΔS.
Where
ΔH= 38.468 kJ/mol = 38468 J/mol
∆S = +51.4 J mol−1 K−1).
T = 25◦C =298k
ΔG= 38468J/mol−298k(51.4 J mol−1 K−1).
ΔG = 38468 J/mol - 15317.2J/mol
ΔG = 23168.8J/mol
ΔG =23.169kJ/mol
Answer:
1.atomic number
2.electron
3.element
4.atom
5.neutron
6.nucleus
7.proton
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particles larger than 5 microns are normally expelled. -particles smaller than 5 microns may enter into alveolar sacs. ... -chemical can penetrate skin and go into bloodstream.
: = 4 : 1
Given that:
Volume of a cylinder = h
For cylinder A, = = and = 4.
Volume of cylinder A = ×
= 4
Volume of cylinder B =
=
To determine the ratio of their masses, density (ρ) is defined as the ratio of the mass (M) of a substance to its volume (V).
i.e ρ =
Thus, since the cylinders are made from the same material, they have the same density (ρ). So that;
density of A = density of B
density of A =
density of B =
⇒ =
The ratio of mass of cylinder A to that of B is given as;
Therefore, : = 4 : 1