3 quarters and 3 pennies, or 7 dimes 1 nickel and 3 pennies
Hope this helps
Answer:
- y = 2x + 3
- y = -6x
- y = -x + 2
- y = 2x - 7
Step-by-step explanation:
<u>Slope-intercept form:</u>
<em>Hint. if we have x = 0, then the y-coordinate is the same as b</em>
<u>Slope</u>
33.
- m = (9 -(-3))/(3 - (-3)) = 12/6 = 2
- b = 3 as per table (0, 3)
34.
- m = (0-12)/(0 - (-2)) = -12/2 = -6
- b = 0, as per table (0, 0)
35.
- m = (2 - (-2))/(0 - 4) = 4/-4 = -1
- b = 2, as per table (0, 2)
36.
- m = (-5 - (-1))/ (1 -3) = -4/-2 = 2
Using point (3, -1)
- -1 = 2*3 + b
- b= -1 - 6= - 7
A. 1/5 fish
We know that 2/5 of Mike's fish are clownfish. Therefore, 3/5 are not clownish as 5/5 – 2/5 = 3/5. Also, if you look at the model, there are five pieces. If we assume that model represents the whole of Mike's fish and you take away two pieces, you are left with 3/5. So we know that the remaining fish is 3/5
Next, we know that of these 3/5 fish, 1/3 is damselfish, so we need to find 1/3 of 3/5. To do this, we must multiply 1/3 by 3/5 as "of" means multiply in Math.
So: 1/3 • 3/5 = 1 • 3/3 • 5 = 3/15 3 ÷ 3 = 1 and 15 ÷ 3 = 5 3/15 = 1/5
1/5 of Mike's fish are damsel fish
B. 2/5 fish
Now we know that 1/5 of Mike's fish is damselfish, and 2/5 is clownfish. To find the fraction of his fish that are neither, therefore, we must subtract their sum from the whole.
First, we add 1/5 and 2/5 together. Adding the numerators, 1 and 2, we get 1/5 + 2/5 = 3/5
Next, we subtract: 5/5 – 3/5 = 2/5, so 2/5 of his fish are neither clownfish or damselfish
And if you look at the model again, you can see that if you cross out 1 piece for the damselfish, and 2 pieces for the clownfish, you are left with 2/5
Answer:
x=126°, y=234°
Step-by-step explanation:
B altrenates A
180-54=126, x=126°
D is 180°, 54+180=234°
