<h3><u>Answer;</u></h3>
<em>-49 °C</em>
<h3><u>Explanation and solution;</u></h3>
- Considering the fact that, the specific heat capacity of aluminum is 0.903 J/g x C, and the heat of vaporization of water at 25 C is 44.0 KJ/mol.
Moles water = 0.48 g / 18.02 g/mol
=0.0266 moles
<em>Heat lost by water</em> = 0.0266 mol x 44.0 kJ/mol
=1.17 kJ => 1170 J
<em>But heat lost =heat gained</em>
<em>Therefore;</em> Heat gained by aluminium = 1170 J
1170 = 55 x 0.903 ( T - 25) = 49.7 T - 1242
1170 + 1242 = 49.7 T
T = 48.5 °C ( 49 °C <em>at two significant figures)</em>
<em>Hence</em>, final temperature = 49 °C
Answer:
Explanation:
Where and are number of moles of product and reactant respectively (equal to their stoichiometric coefficient).
is standard heat of formation and is standard enthalpy change for reaction at
So,
or,
or,
Answer:
If the temperature rises much more, the individual particles will have enough energy to overpower the intermolecular forces, causing the particles to disperse and the material to become a gas (assuming that their chemical bonds are not so weak that the compound decomposes from the high temperature).
Explanation:
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4KO₂ + 2CO₂ → 2K₂CO₃ + 3 O₂
The two chemicals that have a molar ratio of 3:4 is in equation above O₂ and KO₂
<em><u>explanation</u></em>
The molar ratio is the ratio between the amount in moles of two compounds that are involved in a chemical reaction.
In the equation above the mole ratio is determined by examining coefficient ( <em>number in front of the formula</em>)
the coefficient of O₂ is 3 while that of KO₂ is 4 therefore the mole ratio of O₂:KO₂ is 3:4